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51134113124603 = 269918945577297
BaseRepresentation
bin10111010000001100101101…
…01001100001000011111011
320201001101002021002022110222
423220012112221201003323
523200240130424441403
6300430404241330255
713525213664055335
oct1350062651410373
9221041067068428
1051134113124603
1115324945882543
12589a17303698b
13226bc06a72382
14c8ac934ba455
155da1b03a8338
hex2e8196a610fb

51134113124603 has 4 divisors (see below), whose sum is σ = 51153058704600. Its totient is φ = 51115167544608.

The previous prime is 51134113124587. The next prime is 51134113124683. The reversal of 51134113124603 is 30642131143115.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51134113124603 - 24 = 51134113124587 is a prime.

It is a super-2 number, since 2×511341131246032 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51134113124683) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9472785950 + ... + 9472791347.

It is an arithmetic number, because the mean of its divisors is an integer number (12788264676150).

Almost surely, 251134113124603 is an apocalyptic number.

51134113124603 is a deficient number, since it is larger than the sum of its proper divisors (18945579997).

51134113124603 is a wasteful number, since it uses less digits than its factorization.

51134113124603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18945579996.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 51134113124603 its reverse (30642131143115), we get a palindrome (81776244267718).

The spelling of 51134113124603 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred thirteen million, one hundred twenty-four thousand, six hundred three".

Divisors: 1 2699 18945577297 51134113124603