Base | Representation |
---|---|
bin | 1110000000011100100011… |
… | …01101000111001001110001 |
3 | 11001001121110022000022000111 |
4 | 13000032101231013021301 |
5 | 13014123242140023323 |
6 | 145302030204021321 |
7 | 6326226503440141 |
oct | 700162155071161 |
9 | 131047408008014 |
10 | 30801655001713 |
11 | 98a59aa284062 |
12 | 3555697b31841 |
13 | 142577823b57b |
14 | 786b45442921 |
15 | 38634d531c0d |
hex | 1c0391b47271 |
30801655001713 has 2 divisors, whose sum is σ = 30801655001714. Its totient is φ = 30801655001712.
The previous prime is 30801655001633. The next prime is 30801655001749. The reversal of 30801655001713 is 31710055610803.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22645872877824 + 8155782123889 = 4758768^2 + 2855833^2 .
It is a cyclic number.
It is not a de Polignac number, because 30801655001713 - 213 = 30801654993521 is a prime.
It is not a weakly prime, because it can be changed into another prime (30801655001753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15400827500856 + 15400827500857.
It is an arithmetic number, because the mean of its divisors is an integer number (15400827500857).
Almost surely, 230801655001713 is an apocalyptic number.
It is an amenable number.
30801655001713 is a deficient number, since it is larger than the sum of its proper divisors (1).
30801655001713 is an equidigital number, since it uses as much as digits as its factorization.
30801655001713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 40.
The spelling of 30801655001713 in words is "thirty trillion, eight hundred one billion, six hundred fifty-five million, one thousand, seven hundred thirteen".
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