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3100040110402 = 21550020055201
BaseRepresentation
bin101101000111001000110…
…010100010000101000010
3101222100202010101102211021
4231013020302202011002
5401242340232013102
610332045550140054
7436653612110404
oct55071062420502
911870663342737
103100040110402
11a957a0908374
124209851b162a
131964427444c1
14aa0853d8b74
155598c253137
hex2d1c8ca2142

3100040110402 has 4 divisors (see below), whose sum is σ = 4650060165606. Its totient is φ = 1550020055200.

The previous prime is 3100040110381. The next prime is 3100040110403. The reversal of 3100040110402 is 2040110400013.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1601842078321 + 1498198032081 = 1265639^2 + 1224009^2 .

It is a super-2 number, since 2×31000401104022 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (3100040110403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775010027599 + ... + 775010027602.

Almost surely, 23100040110402 is an apocalyptic number.

3100040110402 is a deficient number, since it is larger than the sum of its proper divisors (1550020055204).

3100040110402 is a wasteful number, since it uses less digits than its factorization.

3100040110402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1550020055203.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 3100040110402 its reverse (2040110400013), we get a palindrome (5140150510415).

The spelling of 3100040110402 in words is "three trillion, one hundred billion, forty million, one hundred ten thousand, four hundred two".

Divisors: 1 2 1550020055201 3100040110402