Base | Representation |
---|---|
bin | 101101000111001001000… |
… | …100011110001011000001 |
3 | 101222100202110020100120022 |
4 | 231013021010132023001 |
5 | 401242342433003433 |
6 | 10332050235023225 |
7 | 436654000064522 |
oct | 55071104361301 |
9 | 11870673210508 |
10 | 3100044812993 |
11 | a957a352a507 |
12 | 42098689ab15 |
13 | 1964436ccabb |
14 | aa085ca0849 |
15 | 5598c881698 |
hex | 2d1c911e2c1 |
3100044812993 has 2 divisors, whose sum is σ = 3100044812994. Its totient is φ = 3100044812992.
The previous prime is 3100044812911. The next prime is 3100044813043. The reversal of 3100044812993 is 3992184400013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2603537148304 + 496507664689 = 1613548^2 + 704633^2 .
It is a cyclic number.
It is not a de Polignac number, because 3100044812993 - 212 = 3100044808897 is a prime.
It is a super-2 number, since 2×31000448129932 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3100044812093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1550022406496 + 1550022406497.
It is an arithmetic number, because the mean of its divisors is an integer number (1550022406497).
Almost surely, 23100044812993 is an apocalyptic number.
It is an amenable number.
3100044812993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3100044812993 is an equidigital number, since it uses as much as digits as its factorization.
3100044812993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 44.
The spelling of 3100044812993 in words is "three trillion, one hundred billion, forty-four million, eight hundred twelve thousand, nine hundred ninety-three".
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