Base | Representation |
---|---|
bin | 1001000001011100001… |
… | …10001111000111001011 |
3 | 1002122012012110010221111 |
4 | 10200232012033013023 |
5 | 20034400311011021 |
6 | 354230032151151 |
7 | 31253235202522 |
oct | 4405606170713 |
9 | 1078165403844 |
10 | 310011032011 |
11 | 10a52516687a |
12 | 500ba0984b7 |
13 | 23306bac5a5 |
14 | 1100c9374b9 |
15 | 80e64ea8e1 |
hex | 482e18f1cb |
310011032011 has 2 divisors, whose sum is σ = 310011032012. Its totient is φ = 310011032010.
The previous prime is 310011031823. The next prime is 310011032039. The reversal of 310011032011 is 110230110013.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-310011032011 is a prime.
It is a super-2 number, since 2×3100110320112 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 310011031982 and 310011032000.
It is not a weakly prime, because it can be changed into another prime (310011030011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155005516005 + 155005516006.
It is an arithmetic number, because the mean of its divisors is an integer number (155005516006).
Almost surely, 2310011032011 is an apocalyptic number.
310011032011 is a deficient number, since it is larger than the sum of its proper divisors (1).
310011032011 is an equidigital number, since it uses as much as digits as its factorization.
310011032011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 310011032011 its reverse (110230110013), we get a palindrome (420241142024).
The spelling of 310011032011 in words is "three hundred ten billion, eleven million, thirty-two thousand, eleven".
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