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31001122113 = 313794900567
BaseRepresentation
bin11100110111110011…
…111001010101000001
32222000112002011201220
4130313303321111001
51001442241401423
622124113345253
72145144122133
oct346763712501
988015064656
1031001122113
1112169363985
126012268229
132c00905c50
1417013a9053
15c1697c9e3
hex737cf9541

31001122113 has 8 divisors (see below), whose sum is σ = 44514431808. Its totient is φ = 19077613584.

The previous prime is 31001122111. The next prime is 31001122127. The reversal of 31001122113 is 31122110013.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 31001122113 - 21 = 31001122111 is a prime.

It is a super-2 number, since 2×310011221132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31001122092 and 31001122101.

It is not an unprimeable number, because it can be changed into a prime (31001122111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397450245 + ... + 397450322.

It is an arithmetic number, because the mean of its divisors is an integer number (5564303976).

Almost surely, 231001122113 is an apocalyptic number.

It is an amenable number.

31001122113 is a deficient number, since it is larger than the sum of its proper divisors (13513309695).

31001122113 is a wasteful number, since it uses less digits than its factorization.

31001122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 794900583.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 31001122113 its reverse (31122110013), we get a palindrome (62123232126).

The spelling of 31001122113 in words is "thirty-one billion, one million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 13 39 794900567 2384701701 10333707371 31001122113