Base | Representation |
---|---|
bin | 11100110111110011… |
… | …111001010100111111 |
3 | 2222000112002011201211 |
4 | 130313303321110333 |
5 | 1001442241401421 |
6 | 22124113345251 |
7 | 2145144122131 |
oct | 346763712477 |
9 | 88015064654 |
10 | 31001122111 |
11 | 12169363983 |
12 | 6012268227 |
13 | 2c00905c4b |
14 | 17013a9051 |
15 | c1697c9e1 |
hex | 737cf953f |
31001122111 has 2 divisors, whose sum is σ = 31001122112. Its totient is φ = 31001122110.
The previous prime is 31001122099. The next prime is 31001122127. The reversal of 31001122111 is 11122110013.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31001122111 is a prime.
It is a super-2 number, since 2×310011221112 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31001122091 and 31001122100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31001122181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15500561055 + 15500561056.
It is an arithmetic number, because the mean of its divisors is an integer number (15500561056).
Almost surely, 231001122111 is an apocalyptic number.
31001122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31001122111 is an equidigital number, since it uses as much as digits as its factorization.
31001122111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 31001122111 its reverse (11122110013), we get a palindrome (42123232124).
It can be divided in two parts, 3100 and 1122111, that added together give a palindrome (1125211).
The spelling of 31001122111 in words is "thirty-one billion, one million, one hundred twenty-two thousand, one hundred eleven".
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