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310012993 is a prime number
BaseRepresentation
bin10010011110100…
…110110001000001
3210121100021212201
4102132212301001
51113330403433
650432353201
710453031653
oct2236466101
9717307781
10310012993
11149aa3394
12879a5801
134c2c5554
142d25c6d3
151c33aa7d
hex127a6c41

310012993 has 2 divisors, whose sum is σ = 310012994. Its totient is φ = 310012992.

The previous prime is 310012979. The next prime is 310013027. The reversal of 310012993 is 399210013.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 280495504 + 29517489 = 16748^2 + 5433^2 .

It is an emirp because it is prime and its reverse (399210013) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 310012993 - 25 = 310012961 is a prime.

It is a super-2 number, since 2×3100129932 = 192216111657636098, which contains 22 as substring.

It is equal to p16765201 and since 310012993 and 16765201 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (310012903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155006496 + 155006497.

It is an arithmetic number, because the mean of its divisors is an integer number (155006497).

Almost surely, 2310012993 is an apocalyptic number.

It is an amenable number.

310012993 is a deficient number, since it is larger than the sum of its proper divisors (1).

310012993 is an equidigital number, since it uses as much as digits as its factorization.

310012993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 28.

The square root of 310012993 is about 17607.1858341985. The cubic root of 310012993 is about 676.7994004891.

The spelling of 310012993 in words is "three hundred ten million, twelve thousand, nine hundred ninety-three".