Base | Representation |
---|---|
bin | 11100110111110100… |
… | …100101000000000111 |
3 | 2222000112102021010022 |
4 | 130313310211000013 |
5 | 1001442313112444 |
6 | 22124121245355 |
7 | 2145145465514 |
oct | 346764450007 |
9 | 88015367108 |
10 | 31001300999 |
11 | 12169476319 |
12 | 601233385b |
13 | 2c009694b6 |
14 | 170141430b |
15 | c169b59ee |
hex | 737d25007 |
31001300999 has 4 divisors (see below), whose sum is σ = 32632948440. Its totient is φ = 29369653560.
The previous prime is 31001300987. The next prime is 31001301007. The reversal of 31001300999 is 99900310013.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-31001300999 is a prime.
It is a super-2 number, since 2×310013009992 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31001300959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 815823692 + ... + 815823729.
It is an arithmetic number, because the mean of its divisors is an integer number (8158237110).
Almost surely, 231001300999 is an apocalyptic number.
31001300999 is a deficient number, since it is larger than the sum of its proper divisors (1631647441).
31001300999 is a wasteful number, since it uses less digits than its factorization.
31001300999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1631647440.
The product of its (nonzero) digits is 6561, while the sum is 35.
The spelling of 31001300999 in words is "thirty-one billion, one million, three hundred thousand, nine hundred ninety-nine".
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