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31002120320131 is a prime number
BaseRepresentation
bin1110000110010001111100…
…10111100111010010000011
311001202202220001212121101101
413003020332113213102003
513030414320300221011
6145534102155315231
76346554304513462
oct703107627472203
9131682801777341
1031002120320131
119972a1a773934
12358850344bb17
13143b644a8b98c
1479272124c9d9
1538b68276d2c1
hex1c323e5e7483

31002120320131 has 2 divisors, whose sum is σ = 31002120320132. Its totient is φ = 31002120320130.

The previous prime is 31002120320057. The next prime is 31002120320159. The reversal of 31002120320131 is 13102302120013.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31002120320131 - 215 = 31002120287363 is a prime.

It is a super-2 number, since 2×310021203201312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31002120320099 and 31002120320108.

It is not a weakly prime, because it can be changed into another prime (31002120320531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15501060160065 + 15501060160066.

It is an arithmetic number, because the mean of its divisors is an integer number (15501060160066).

Almost surely, 231002120320131 is an apocalyptic number.

31002120320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31002120320131 is an equidigital number, since it uses as much as digits as its factorization.

31002120320131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 31002120320131 its reverse (13102302120013), we get a palindrome (44104422440144).

The spelling of 31002120320131 in words is "thirty-one trillion, two billion, one hundred twenty million, three hundred twenty thousand, one hundred thirty-one".