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310120131129947 is a prime number
BaseRepresentation
bin100011010000011010111100…
…0010000001111001001011011
31111200001012021011002112122122
41012200311320100033021123
5311122002012032124242
63015323115500211455
7122215303643655005
oct10640657020171133
91450035234075578
10310120131129947
118a8a5233231516
122a947438539b8b
131040728396a588
145681c74483375
1525cbe0a00aad2
hex11a0d7840f25b

310120131129947 has 2 divisors, whose sum is σ = 310120131129948. Its totient is φ = 310120131129946.

The previous prime is 310120131129929. The next prime is 310120131130151. The reversal of 310120131129947 is 749921131021013.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-310120131129947 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 310120131129898 and 310120131129907.

It is not a weakly prime, because it can be changed into another prime (310120131129247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155060065564973 + 155060065564974.

It is an arithmetic number, because the mean of its divisors is an integer number (155060065564974).

Almost surely, 2310120131129947 is an apocalyptic number.

310120131129947 is a deficient number, since it is larger than the sum of its proper divisors (1).

310120131129947 is an equidigital number, since it uses as much as digits as its factorization.

310120131129947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 44.

The spelling of 310120131129947 in words is "three hundred ten trillion, one hundred twenty billion, one hundred thirty-one million, one hundred twenty-nine thousand, nine hundred forty-seven".