Base | Representation |
---|---|
bin | 101101001000001110100… |
… | …001010110110101001001 |
3 | 101222110202122202122111011 |
4 | 231020032201112311021 |
5 | 401302234230404001 |
6 | 10332402021203521 |
7 | 440024606113222 |
oct | 55101641266511 |
9 | 11873678678434 |
10 | 3101210013001 |
11 | a96241227521 |
12 | 421050b605a1 |
13 | 19659ac2b569 |
14 | aa156932249 |
15 | 55a09ce5d51 |
hex | 2d20e856d49 |
3101210013001 has 2 divisors, whose sum is σ = 3101210013002. Its totient is φ = 3101210013000.
The previous prime is 3101210012993. The next prime is 3101210013047. The reversal of 3101210013001 is 1003100121013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1624985013001 + 1476225000000 = 1274749^2 + 1215000^2 .
It is a cyclic number.
It is not a de Polignac number, because 3101210013001 - 23 = 3101210012993 is a prime.
It is not a weakly prime, because it can be changed into another prime (3101210010001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1550605006500 + 1550605006501.
It is an arithmetic number, because the mean of its divisors is an integer number (1550605006501).
Almost surely, 23101210013001 is an apocalyptic number.
It is an amenable number.
3101210013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3101210013001 is an equidigital number, since it uses as much as digits as its factorization.
3101210013001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 3101210013001 its reverse (1003100121013), we get a palindrome (4104310134014).
The spelling of 3101210013001 in words is "three trillion, one hundred one billion, two hundred ten million, thirteen thousand, one".
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