Base | Representation |
---|---|
bin | 101101001001000101110… |
… | …011110110011000110011 |
3 | 101222120011022012100020112 |
4 | 231021011303312120303 |
5 | 401311134211421411 |
6 | 10333034034531535 |
7 | 440056601412101 |
oct | 55110563663063 |
9 | 11876138170215 |
10 | 3102137607731 |
11 | a96677897138 |
12 | 42126b736bab |
13 | 1966b8167196 |
14 | aa203bd2c71 |
15 | 55a61473b8b |
hex | 2d245cf6633 |
3102137607731 has 2 divisors, whose sum is σ = 3102137607732. Its totient is φ = 3102137607730.
The previous prime is 3102137607707. The next prime is 3102137607761. The reversal of 3102137607731 is 1377067312013.
3102137607731 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3102137607731 is a prime.
It is a super-2 number, since 2×31021376077312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3102137607761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1551068803865 + 1551068803866.
It is an arithmetic number, because the mean of its divisors is an integer number (1551068803866).
Almost surely, 23102137607731 is an apocalyptic number.
3102137607731 is a deficient number, since it is larger than the sum of its proper divisors (1).
3102137607731 is an equidigital number, since it uses as much as digits as its factorization.
3102137607731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 111132, while the sum is 41.
The spelling of 3102137607731 in words is "three trillion, one hundred two billion, one hundred thirty-seven million, six hundred seven thousand, seven hundred thirty-one".
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