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31023000032014 = 2105122063668939
BaseRepresentation
bin1110000110111000110101…
…11001011001001100001110
311001211202210012201212110201
413003130122321121030032
513031240101002011024
6145551434112124114
76351223601240164
oct703343271311416
9131752705655421
1031023000032014
119980864828471
12359056bb3663a
1314405c17a8693
147937422cd234
1538bea5859744
hex1c371ae5930e

31023000032014 has 16 divisors (see below), whose sum is σ = 46580957256960. Its totient is φ = 15496015663800.

The previous prime is 31023000031993. The next prime is 31023000032041. The reversal of 31023000032014 is 41023000032013.

It is a junction number, because it is equal to n+sod(n) for n = 31023000031982 and 31023000032000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46041957 + ... + 46710895.

It is an arithmetic number, because the mean of its divisors is an integer number (2911309828560).

Almost surely, 231023000032014 is an apocalyptic number.

31023000032014 is a deficient number, since it is larger than the sum of its proper divisors (15557957224946).

31023000032014 is a wasteful number, since it uses less digits than its factorization.

31023000032014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 692055.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 31023000032014 its reverse (41023000032013), we get a palindrome (72046000064027).

Subtracting 31023000032014 from its reverse (41023000032013), we obtain a palindrome (9999999999999).

The spelling of 31023000032014 in words is "thirty-one trillion, twenty-three billion, thirty-two thousand, fourteen".

Divisors: 1 2 1051 2102 22063 44126 668939 1337878 23188213 46376426 703054889 1406109778 14758801157 29517602314 15511500016007 31023000032014