Base | Representation |
---|---|
bin | 1110000111000110000100… |
… | …00110011000101001000011 |
3 | 11001212110010000221202220111 |
4 | 13003203002012120221003 |
5 | 13031344121122400003 |
6 | 145555010425252151 |
7 | 6351564544541332 |
oct | 703430206305103 |
9 | 131773100852814 |
10 | 31030100200003 |
11 | 99838786787a3 |
12 | 3591a11934057 |
13 | 1441183783708 |
14 | 793c17281d19 |
15 | 38c26dd5ce6d |
hex | 1c38c2198a43 |
31030100200003 has 2 divisors, whose sum is σ = 31030100200004. Its totient is φ = 31030100200002.
The previous prime is 31030100199953. The next prime is 31030100200049. The reversal of 31030100200003 is 30000200103013.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31030100200003 - 233 = 31021510265411 is a prime.
It is not a weakly prime, because it can be changed into another prime (31030100200103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15515050100001 + 15515050100002.
It is an arithmetic number, because the mean of its divisors is an integer number (15515050100002).
Almost surely, 231030100200003 is an apocalyptic number.
31030100200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
31030100200003 is an equidigital number, since it uses as much as digits as its factorization.
31030100200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 31030100200003 its reverse (30000200103013), we get a palindrome (61030300303016).
The spelling of 31030100200003 in words is "thirty-one trillion, thirty billion, one hundred million, two hundred thousand, three".
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