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3103143044011 = 4088375903017
BaseRepresentation
bin101101001010000001101…
…111010010001110101011
3101222122202101002210112021
4231022001233102032223
5401320214104402021
610333321512525311
7440123530444153
oct55120157221653
911878671083467
103103143044011
11a9704339330a
124214b03b0837
131968185588aa
14aa29b557763
1555abe87ac41
hex2d281bd23ab

3103143044011 has 4 divisors (see below), whose sum is σ = 3103218987912. Its totient is φ = 3103067100112.

The previous prime is 3103143043993. The next prime is 3103143044041. The reversal of 3103143044011 is 1104403413013.

It is a happy number.

3103143044011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3103143044011 - 27 = 3103143043883 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3103143044041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37910626 + ... + 37992391.

It is an arithmetic number, because the mean of its divisors is an integer number (775804746978).

Almost surely, 23103143044011 is an apocalyptic number.

3103143044011 is a deficient number, since it is larger than the sum of its proper divisors (75943901).

3103143044011 is an equidigital number, since it uses as much as digits as its factorization.

3103143044011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75943900.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 3103143044011 its reverse (1104403413013), we get a palindrome (4207546457024).

The spelling of 3103143044011 in words is "three trillion, one hundred three billion, one hundred forty-three million, forty-four thousand, eleven".

Divisors: 1 40883 75903017 3103143044011