Base | Representation |
---|---|
bin | 101101001010000101001… |
… | …001011011111111111111 |
3 | 101222122220100201012220120 |
4 | 231022011021123333333 |
5 | 401320323224401143 |
6 | 10333331314350023 |
7 | 440125123515255 |
oct | 55120511337777 |
9 | 11878810635816 |
10 | 3103200231423 |
11 | a970726a3036 |
12 | 42150758b313 |
13 | 19682735c5b6 |
14 | aa2a4da25d5 |
15 | 55ac48c5383 |
hex | 2d28525bfff |
3103200231423 has 16 divisors (see below), whose sum is σ = 4202881344000. Its totient is φ = 2036256928160.
The previous prime is 3103200231413. The next prime is 3103200231431. The reversal of 3103200231423 is 3241320023013.
It is a cyclic number.
It is not a de Polignac number, because 3103200231423 - 212 = 3103200227327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3103200231393 and 3103200231402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3103200231413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12033528 + ... + 12288701.
It is an arithmetic number, because the mean of its divisors is an integer number (262680084000).
Almost surely, 23103200231423 is an apocalyptic number.
3103200231423 is a deficient number, since it is larger than the sum of its proper divisors (1099681112577).
3103200231423 is a wasteful number, since it uses less digits than its factorization.
3103200231423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24322902.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 3103200231423 its reverse (3241320023013), we get a palindrome (6344520254436).
The spelling of 3103200231423 in words is "three trillion, one hundred three billion, two hundred million, two hundred thirty-one thousand, four hundred twenty-three".
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