Base | Representation |
---|---|
bin | 11100111010001101… |
… | …001101010101111001 |
3 | 2222010022201001001201 |
4 | 130322031031111321 |
5 | 1002033033441441 |
6 | 22132111014201 |
7 | 2146142541151 |
oct | 347215152571 |
9 | 88108631051 |
10 | 31041312121 |
11 | 1218a014266 |
12 | 602380a361 |
13 | 2c09038111 |
14 | 170686b761 |
15 | c1a26ac31 |
hex | 73a34d579 |
31041312121 has 2 divisors, whose sum is σ = 31041312122. Its totient is φ = 31041312120.
The previous prime is 31041312089. The next prime is 31041312151. The reversal of 31041312121 is 12121314013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17582760000 + 13458552121 = 132600^2 + 116011^2 .
It is an emirp because it is prime and its reverse (12121314013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31041312121 - 25 = 31041312089 is a prime.
It is not a weakly prime, because it can be changed into another prime (31041312151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15520656060 + 15520656061.
It is an arithmetic number, because the mean of its divisors is an integer number (15520656061).
Almost surely, 231041312121 is an apocalyptic number.
It is an amenable number.
31041312121 is a deficient number, since it is larger than the sum of its proper divisors (1).
31041312121 is an equidigital number, since it uses as much as digits as its factorization.
31041312121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31041312121 its reverse (12121314013), we get a palindrome (43162626134).
The spelling of 31041312121 in words is "thirty-one billion, forty-one million, three hundred twelve thousand, one hundred twenty-one".
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