Base | Representation |
---|---|
bin | 100011010110110100101011… |
… | …1001110100100101011100011 |
3 | 1111210011022110212220211220001 |
4 | 1012231221113032210223203 |
5 | 311230411043101411121 |
6 | 3021235240511400431 |
7 | 122336004021236206 |
oct | 10655512716445343 |
9 | 1453138425824801 |
10 | 311000045341411 |
11 | 90104418928078 |
12 | 2aa69a85b23117 |
13 | 1046c2420429ba |
14 | 56b26a801193d |
15 | 25e4c58ec2991 |
hex | 11ada573a4ae3 |
311000045341411 has 2 divisors, whose sum is σ = 311000045341412. Its totient is φ = 311000045341410.
The previous prime is 311000045341291. The next prime is 311000045341483. The reversal of 311000045341411 is 114143540000113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311000045341411 - 29 = 311000045340899 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 311000045341411.
It is not a weakly prime, because it can be changed into another prime (311000045341211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500022670705 + 155500022670706.
It is an arithmetic number, because the mean of its divisors is an integer number (155500022670706).
Almost surely, 2311000045341411 is an apocalyptic number.
311000045341411 is a deficient number, since it is larger than the sum of its proper divisors (1).
311000045341411 is an equidigital number, since it uses as much as digits as its factorization.
311000045341411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 311000045341411 its reverse (114143540000113), we get a palindrome (425143585341524).
The spelling of 311000045341411 in words is "three hundred eleven trillion, forty-five million, three hundred forty-one thousand, four hundred eleven".
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