Base | Representation |
---|---|
bin | 100011010110110100101101… |
… | …1001100111001101111011011 |
3 | 1111210011022122112101002002102 |
4 | 1012231221123030321233123 |
5 | 311230411212133343001 |
6 | 3021235251252354015 |
7 | 122336005461025634 |
oct | 10655513314715733 |
9 | 1453138575332072 |
10 | 311000112012251 |
11 | 90104452524942 |
12 | 2aa69aa431590b |
13 | 1046c252ab70bc |
14 | 56b26b2c0888b |
15 | 25e4c5ec91e6b |
hex | 11ada5b339bdb |
311000112012251 has 2 divisors, whose sum is σ = 311000112012252. Its totient is φ = 311000112012250.
The previous prime is 311000112012229. The next prime is 311000112012257. The reversal of 311000112012251 is 152210211000113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311000112012251 is a prime.
It is not a weakly prime, because it can be changed into another prime (311000112012257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500056006125 + 155500056006126.
It is an arithmetic number, because the mean of its divisors is an integer number (155500056006126).
Almost surely, 2311000112012251 is an apocalyptic number.
311000112012251 is a deficient number, since it is larger than the sum of its proper divisors (1).
311000112012251 is an equidigital number, since it uses as much as digits as its factorization.
311000112012251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 311000112012251 its reverse (152210211000113), we get a palindrome (463210323012364).
The spelling of 311000112012251 in words is "three hundred eleven trillion, one hundred twelve million, twelve thousand, two hundred fifty-one".
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