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311001213113 is a prime number
BaseRepresentation
bin1001000011010010001…
…11011110100010111001
31002201202012122120001122
410201221013132202321
520043412302304423
6354512203155025
731316620460063
oct4415107364271
91081665576048
10311001213113
1110a993093568
1250335815a75
132343408c476
14110a424a733
1581533dc8c8
hex48691de8b9

311001213113 has 2 divisors, whose sum is σ = 311001213114. Its totient is φ = 311001213112.

The previous prime is 311001213109. The next prime is 311001213121. The reversal of 311001213113 is 311312100113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 309299485609 + 1701727504 = 556147^2 + 41252^2 .

It is a cyclic number.

It is not a de Polignac number, because 311001213113 - 22 = 311001213109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311001213091 and 311001213100.

It is not a weakly prime, because it can be changed into another prime (311001513113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500606556 + 155500606557.

It is an arithmetic number, because the mean of its divisors is an integer number (155500606557).

Almost surely, 2311001213113 is an apocalyptic number.

It is an amenable number.

311001213113 is a deficient number, since it is larger than the sum of its proper divisors (1).

311001213113 is an equidigital number, since it uses as much as digits as its factorization.

311001213113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 311001213113 its reverse (311312100113), we get a palindrome (622313313226).

The spelling of 311001213113 in words is "three hundred eleven billion, one million, two hundred thirteen thousand, one hundred thirteen".