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311001302013 = 3472205682993
BaseRepresentation
bin1001000011010010001…
…11110100001111111101
31002201202012211002000020
410201221013310033331
520043412313131023
6354512205122353
731316621310213
oct4415107641775
91081665732006
10311001302013
1110a993144336
12503358593b9
13234340c0a7c
14110a4270cb3
158153408de3
hex48691f43fd

311001302013 has 8 divisors (see below), whose sum is σ = 423491134848. Its totient is φ = 202922835264.

The previous prime is 311001302011. The next prime is 311001302047. The reversal of 311001302013 is 310203100113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 311001302013 - 21 = 311001302011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311001301983 and 311001302001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311001302011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1102841356 + ... + 1102841637.

It is an arithmetic number, because the mean of its divisors is an integer number (52936391856).

Almost surely, 2311001302013 is an apocalyptic number.

It is an amenable number.

311001302013 is a deficient number, since it is larger than the sum of its proper divisors (112489832835).

311001302013 is a wasteful number, since it uses less digits than its factorization.

311001302013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2205683043.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 311001302013 its reverse (310203100113), we get a palindrome (621204402126).

The spelling of 311001302013 in words is "three hundred eleven billion, one million, three hundred two thousand, thirteen".

Divisors: 1 3 47 141 2205682993 6617048979 103667100671 311001302013