311001312022123 has 2 divisors, whose sum is σ = 311001312022124. Its totient is φ = 311001312022122.

The previous prime is 311001312021989. The next prime is 311001312022147. The reversal of 311001312022123 is 321220213100113.

It is a strong prime.

It is an emirp because it is prime and its reverse (321220213100113) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311001312022123 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311001312022094 and 311001312022103.

It is not a weakly prime, because it can be changed into another prime (311001312022183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500656011061 + 155500656011062.

It is an arithmetic number, because the mean of its divisors is an integer number (155500656011062).

Almost surely, 2^{311001312022123} is an apocalyptic number.

311001312022123 is a deficient number, since it is larger than the sum of its proper divisors (1).

311001312022123 is an equidigital number, since it uses as much as digits as its factorization.

311001312022123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 311001312022123 its reverse (321220213100113), we get a palindrome (632221525122236).

The spelling of 311001312022123 in words is "three hundred eleven trillion, one billion, three hundred twelve million, twenty-two thousand, one hundred twenty-three".