Base | Representation |
---|---|
bin | 1011100101011111… |
… | …0010011111111001 |
3 | 22000202001102221011 |
4 | 2321113302133321 |
5 | 22332131133423 |
6 | 1232334313521 |
7 | 140032512643 |
oct | 27127623771 |
9 | 8022042834 |
10 | 3110021113 |
11 | 1356586991 |
12 | 7296588a1 |
13 | 3a74263a4 |
14 | 217085893 |
15 | 133077b0d |
hex | b95f27f9 |
3110021113 has 2 divisors, whose sum is σ = 3110021114. Its totient is φ = 3110021112.
The previous prime is 3110021087. The next prime is 3110021119. The reversal of 3110021113 is 3111200113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1971093609 + 1138927504 = 44397^2 + 33748^2 .
It is a cyclic number.
It is not a de Polignac number, because 3110021113 - 217 = 3109890041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3110021093 and 3110021102.
It is not a weakly prime, because it can be changed into another prime (3110021119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555010556 + 1555010557.
It is an arithmetic number, because the mean of its divisors is an integer number (1555010557).
Almost surely, 23110021113 is an apocalyptic number.
It is an amenable number.
3110021113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110021113 is an equidigital number, since it uses as much as digits as its factorization.
3110021113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
The square root of 3110021113 is about 55767.5632693414. The cubic root of 3110021113 is about 1459.6692052533.
Adding to 3110021113 its reverse (3111200113), we get a palindrome (6221221226).
The spelling of 3110021113 in words is "three billion, one hundred ten million, twenty-one thousand, one hundred thirteen".
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