Base | Representation |
---|---|
bin | 11100111101110000… |
… | …111000000001010001 |
3 | 2222021111000011200111 |
4 | 130331300320001101 |
5 | 1002143323243432 |
6 | 22142042121321 |
7 | 2150466040531 |
oct | 347560700121 |
9 | 88244004614 |
10 | 31100993617 |
11 | 1220a777911 |
12 | 603b7b0241 |
13 | 2c18503105 |
14 | 17107654c1 |
15 | c20609347 |
hex | 73dc38051 |
31100993617 has 2 divisors, whose sum is σ = 31100993618. Its totient is φ = 31100993616.
The previous prime is 31100993593. The next prime is 31100993639. The reversal of 31100993617 is 71639900113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27554672016 + 3546321601 = 165996^2 + 59551^2 .
It is an emirp because it is prime and its reverse (71639900113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31100993617 - 223 = 31092605009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31100993617.
It is not a weakly prime, because it can be changed into another prime (31100993687) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550496808 + 15550496809.
It is an arithmetic number, because the mean of its divisors is an integer number (15550496809).
Almost surely, 231100993617 is an apocalyptic number.
It is an amenable number.
31100993617 is a deficient number, since it is larger than the sum of its proper divisors (1).
31100993617 is an equidigital number, since it uses as much as digits as its factorization.
31100993617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30618, while the sum is 40.
The spelling of 31100993617 in words is "thirty-one billion, one hundred million, nine hundred ninety-three thousand, six hundred seventeen".
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