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311012243321134 = 21671721541065881
BaseRepresentation
bin100011010110111010010111…
…0010010001011000100101110
31111210012110221222120102100211
41012231310232102023010232
5311231111033242234014
63021245015132413034
7122336615215324255
oct10655645622130456
91453173858512324
10311012243321134
1190109608311853
122aa7030b01717a
1310470437205094
1456b310404779c
1525e521ecedcc4
hex11add2e48b12e

311012243321134 has 16 divisors (see below), whose sum is σ = 469584586197216. Its totient is φ = 154485130057600.

The previous prime is 311012243321113. The next prime is 311012243321179. The reversal of 311012243321134 is 431123342210113.

It is a junction number, because it is equal to n+sod(n) for n = 311012243321096 and 311012243321105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269958127 + ... + 271107754.

It is an arithmetic number, because the mean of its divisors is an integer number (29349036637326).

Almost surely, 2311012243321134 is an apocalyptic number.

311012243321134 is a deficient number, since it is larger than the sum of its proper divisors (158572342876082).

311012243321134 is a wasteful number, since it uses less digits than its factorization.

311012243321134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 541067771.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 311012243321134 its reverse (431123342210113), we get a palindrome (742135585531247).

The spelling of 311012243321134 in words is "three hundred eleven trillion, twelve billion, two hundred forty-three million, three hundred twenty-one thousand, one hundred thirty-four".

Divisors: 1 2 167 334 1721 3442 287407 574814 541065881 1082131762 90358002127 180716004254 931174381201 1862348762402 155506121660567 311012243321134