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3110123121233 is a prime number
BaseRepresentation
bin101101010000100001110…
…010001010101001010001
3102000022202211100110101212
4231100201302022221101
5401424013004334413
610340434300105505
7440461515225422
oct55204162125121
912008684313355
103110123121233
11a99aa546a677
12422919b35295
1319738b6a75bb
14aa7605a9649
1555d7c55bca8
hex2d421c8aa51

3110123121233 has 2 divisors, whose sum is σ = 3110123121234. Its totient is φ = 3110123121232.

The previous prime is 3110123121187. The next prime is 3110123121239. The reversal of 3110123121233 is 3321213210113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3087354725569 + 22768395664 = 1757087^2 + 150892^2 .

It is a cyclic number.

It is not a de Polignac number, because 3110123121233 - 212 = 3110123117137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3110123121199 and 3110123121208.

It is not a weakly prime, because it can be changed into another prime (3110123121239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555061560616 + 1555061560617.

It is an arithmetic number, because the mean of its divisors is an integer number (1555061560617).

Almost surely, 23110123121233 is an apocalyptic number.

It is an amenable number.

3110123121233 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110123121233 is an equidigital number, since it uses as much as digits as its factorization.

3110123121233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 3110123121233 its reverse (3321213210113), we get a palindrome (6431336331346).

The spelling of 3110123121233 in words is "three trillion, one hundred ten billion, one hundred twenty-three million, one hundred twenty-one thousand, two hundred thirty-three".