Base | Representation |
---|---|
bin | 1001000011010011101… |
… | …00100001000111010001 |
3 | 1002201210000212102012221 |
4 | 10201221310201013101 |
5 | 20043423313120423 |
6 | 354513304221041 |
7 | 31320123023605 |
oct | 4415164410721 |
9 | 1081700772187 |
10 | 311013020113 |
11 | 10a999818314 |
12 | 5033976a781 |
13 | 23436664663 |
14 | 110a5a41505 |
15 | 8154470e5d |
hex | 4869d211d1 |
311013020113 has 2 divisors, whose sum is σ = 311013020114. Its totient is φ = 311013020112.
The previous prime is 311013020081. The next prime is 311013020117. The reversal of 311013020113 is 311020310113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 256230340864 + 54782679249 = 506192^2 + 234057^2 .
It is a cyclic number.
It is not a de Polignac number, because 311013020113 - 25 = 311013020081 is a prime.
It is not a weakly prime, because it can be changed into another prime (311013020117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155506510056 + 155506510057.
It is an arithmetic number, because the mean of its divisors is an integer number (155506510057).
Almost surely, 2311013020113 is an apocalyptic number.
It is an amenable number.
311013020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
311013020113 is an equidigital number, since it uses as much as digits as its factorization.
311013020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 311013020113 its reverse (311020310113), we get a palindrome (622033330226).
Subtracting 311013020113 from its reverse (311020310113), we obtain a square (7290000 = 27002).
The spelling of 311013020113 in words is "three hundred eleven billion, thirteen million, twenty thousand, one hundred thirteen".
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