Base | Representation |
---|---|
bin | 11100111101110010… |
… | …011110001010110111 |
3 | 2222021111210102122000 |
4 | 130331302132022313 |
5 | 1002143430141043 |
6 | 22142055110343 |
7 | 2150502432423 |
oct | 347562361267 |
9 | 88244712560 |
10 | 31101412023 |
11 | 1220aa33200 |
12 | 603b9723b3 |
13 | 2c1861b6a6 |
14 | 1710833b83 |
15 | c2068d2d3 |
hex | 73dc9e2b7 |
31101412023 has 24 divisors (see below), whose sum is σ = 50645708400. Its totient is φ = 18849338640.
The previous prime is 31101411983. The next prime is 31101412033. The reversal of 31101412023 is 32021410113.
It is not a de Polignac number, because 31101412023 - 224 = 31084634807 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31101411987 and 31101412005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31101412033) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4756668 + ... + 4763201.
It is an arithmetic number, because the mean of its divisors is an integer number (2110237850).
Almost surely, 231101412023 is an apocalyptic number.
31101412023 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31101412023 is a deficient number, since it is larger than the sum of its proper divisors (19544296377).
31101412023 is a wasteful number, since it uses less digits than its factorization.
31101412023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9519900 (or 9519883 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 31101412023 its reverse (32021410113), we get a palindrome (63122822136).
The spelling of 31101412023 in words is "thirty-one billion, one hundred one million, four hundred twelve thousand, twenty-three".
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