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311014443130102 = 2155507221565051
BaseRepresentation
bin100011010110111011011000…
…1011001110001110011110110
31111210012200122021220021222001
41012231312301121301303312
5311231130034420130402
63021250021314125514
7122340023556356425
oct10655666131616366
91453180567807861
10311014443130102
119010a537020898
122aa7082388089a
13104706c7b9a7aa
1456b32722752bc
1525e52ecece187
hex11addb1671cf6

311014443130102 has 4 divisors (see below), whose sum is σ = 466521664695156. Its totient is φ = 155507221565050.

The previous prime is 311014443130091. The next prime is 311014443130147. The reversal of 311014443130102 is 201031344410113.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×3110144431301022 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77753610782524 + ... + 77753610782527.

It is an arithmetic number, because the mean of its divisors is an integer number (116630416173789).

Almost surely, 2311014443130102 is an apocalyptic number.

311014443130102 is a deficient number, since it is larger than the sum of its proper divisors (155507221565054).

311014443130102 is a wasteful number, since it uses less digits than its factorization.

311014443130102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155507221565053.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 311014443130102 its reverse (201031344410113), we get a palindrome (512045787540215).

The spelling of 311014443130102 in words is "three hundred eleven trillion, fourteen billion, four hundred forty-three million, one hundred thirty thousand, one hundred two".

Divisors: 1 2 155507221565051 311014443130102