Base | Representation |
---|---|
bin | 101101010000100110010… |
… | …101011110010111100011 |
3 | 102000022222011001012001201 |
4 | 231100212111132113203 |
5 | 401424142032022143 |
6 | 10340450024542031 |
7 | 440463433301125 |
oct | 55204625362743 |
9 | 12008864035051 |
10 | 3110199485923 |
11 | a9a034588592 |
12 | 42293b621917 |
13 | 1973a14640ca |
14 | aa76a7a7215 |
15 | 55d840e364d |
hex | 2d42655e5e3 |
3110199485923 has 2 divisors, whose sum is σ = 3110199485924. Its totient is φ = 3110199485922.
The previous prime is 3110199485917. The next prime is 3110199485977. The reversal of 3110199485923 is 3295849910113.
It is a weak prime.
It is an emirp because it is prime and its reverse (3295849910113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3110199485923 - 25 = 3110199485891 is a prime.
It is not a weakly prime, because it can be changed into another prime (3110199485983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555099742961 + 1555099742962.
It is an arithmetic number, because the mean of its divisors is an integer number (1555099742962).
Almost surely, 23110199485923 is an apocalyptic number.
3110199485923 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110199485923 is an equidigital number, since it uses as much as digits as its factorization.
3110199485923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 55.
The spelling of 3110199485923 in words is "three trillion, one hundred ten billion, one hundred ninety-nine million, four hundred eighty-five thousand, nine hundred twenty-three".
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