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31102059041 is a prime number
BaseRepresentation
bin11100111101110100…
…111100001000100001
32222021120000022011122
4130331310330020201
51002144111342131
622142121022025
72150511065654
oct347564741041
988246008148
1031102059041
1112210335329
126040024915
132c187b7041
14171096189b
15c20769d7b
hex73dd3c221

31102059041 has 2 divisors, whose sum is σ = 31102059042. Its totient is φ = 31102059040.

The previous prime is 31102059029. The next prime is 31102059047. The reversal of 31102059041 is 14095020113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29589160225 + 1512898816 = 172015^2 + 38896^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31102059041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31102059041.

It is not a weakly prime, because it can be changed into another prime (31102059047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551029520 + 15551029521.

It is an arithmetic number, because the mean of its divisors is an integer number (15551029521).

Almost surely, 231102059041 is an apocalyptic number.

It is an amenable number.

31102059041 is a deficient number, since it is larger than the sum of its proper divisors (1).

31102059041 is an equidigital number, since it uses as much as digits as its factorization.

31102059041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 26.

Adding to 31102059041 its reverse (14095020113), we get a palindrome (45197079154).

The spelling of 31102059041 in words is "thirty-one billion, one hundred two million, fifty-nine thousand, forty-one".