Base | Representation |
---|---|
bin | 1110001001001100001011… |
… | …01100000001011010110011 |
3 | 11002010022221220100110212012 |
4 | 13010212011230001122303 |
5 | 13034034100340201321 |
6 | 150052035154353135 |
7 | 6360024026232311 |
oct | 704460554013263 |
9 | 132108856313765 |
10 | 31102101100211 |
11 | 9a013662717a9 |
12 | 35a396688b7ab |
13 | 1447bb95cc08b |
14 | 7974c79090b1 |
15 | 38e084e5d05b |
hex | 1c4985b016b3 |
31102101100211 has 2 divisors, whose sum is σ = 31102101100212. Its totient is φ = 31102101100210.
The previous prime is 31102101100171. The next prime is 31102101100271. The reversal of 31102101100211 is 11200110120113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31102101100211 - 210 = 31102101099187 is a prime.
It is a super-3 number, since 3×311021011002113 (a number of 41 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (31102101100271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551050550105 + 15551050550106.
It is an arithmetic number, because the mean of its divisors is an integer number (15551050550106).
Almost surely, 231102101100211 is an apocalyptic number.
31102101100211 is a deficient number, since it is larger than the sum of its proper divisors (1).
31102101100211 is an equidigital number, since it uses as much as digits as its factorization.
31102101100211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 31102101100211 its reverse (11200110120113), we get a palindrome (42302211220324).
The spelling of 31102101100211 in words is "thirty-one trillion, one hundred two billion, one hundred one million, one hundred thousand, two hundred eleven".
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