Base | Representation |
---|---|
bin | 1001000011010100110… |
… | …11000101101010110001 |
3 | 1002201210201220010011211 |
4 | 10201222123011222301 |
5 | 20043433410200223 |
6 | 354514305040121 |
7 | 31320304665406 |
oct | 4415233055261 |
9 | 1081721803154 |
10 | 311023131313 |
11 | 10a9a44a3a84 |
12 | 50341026041 |
13 | 23438794a0b |
14 | 110a71142ad |
15 | 81552bbd0d |
hex | 486a6c5ab1 |
311023131313 has 2 divisors, whose sum is σ = 311023131314. Its totient is φ = 311023131312.
The previous prime is 311023131281. The next prime is 311023131361. The reversal of 311023131313 is 313131320113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 195954958224 + 115068173089 = 442668^2 + 339217^2 .
It is an emirp because it is prime and its reverse (313131320113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311023131313 - 25 = 311023131281 is a prime.
It is a super-2 number, since 2×3110231313132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311023111313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155511565656 + 155511565657.
It is an arithmetic number, because the mean of its divisors is an integer number (155511565657).
Almost surely, 2311023131313 is an apocalyptic number.
It is an amenable number.
311023131313 is a deficient number, since it is larger than the sum of its proper divisors (1).
311023131313 is an equidigital number, since it uses as much as digits as its factorization.
311023131313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 311023131313 its reverse (313131320113), we get a palindrome (624154451426).
The spelling of 311023131313 in words is "three hundred eleven billion, twenty-three million, one hundred thirty-one thousand, three hundred thirteen".
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