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311023131313 is a prime number
BaseRepresentation
bin1001000011010100110…
…11000101101010110001
31002201210201220010011211
410201222123011222301
520043433410200223
6354514305040121
731320304665406
oct4415233055261
91081721803154
10311023131313
1110a9a44a3a84
1250341026041
1323438794a0b
14110a71142ad
1581552bbd0d
hex486a6c5ab1

311023131313 has 2 divisors, whose sum is σ = 311023131314. Its totient is φ = 311023131312.

The previous prime is 311023131281. The next prime is 311023131361. The reversal of 311023131313 is 313131320113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195954958224 + 115068173089 = 442668^2 + 339217^2 .

It is an emirp because it is prime and its reverse (313131320113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311023131313 - 25 = 311023131281 is a prime.

It is a super-2 number, since 2×3110231313132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311023111313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155511565656 + 155511565657.

It is an arithmetic number, because the mean of its divisors is an integer number (155511565657).

Almost surely, 2311023131313 is an apocalyptic number.

It is an amenable number.

311023131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

311023131313 is an equidigital number, since it uses as much as digits as its factorization.

311023131313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 311023131313 its reverse (313131320113), we get a palindrome (624154451426).

The spelling of 311023131313 in words is "three hundred eleven billion, twenty-three million, one hundred thirty-one thousand, three hundred thirteen".