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311032424137 is a prime number
BaseRepresentation
bin1001000011010101111…
…10100010011011001001
31002201211101101020112111
410201222332202123021
520043443300033022
6354515240142321
731320446661241
oct4415276423311
91081741336474
10311032424137
1110a9a97708a6
12503441679a1
132343a699726
14110a8452b21
158156005477
hex486afa26c9

311032424137 has 2 divisors, whose sum is σ = 311032424138. Its totient is φ = 311032424136.

The previous prime is 311032424111. The next prime is 311032424141. The reversal of 311032424137 is 731424230113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 214180137616 + 96852286521 = 462796^2 + 311211^2 .

It is an emirp because it is prime and its reverse (731424230113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311032424137 - 27 = 311032424009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311032424099 and 311032424108.

It is not a weakly prime, because it can be changed into another prime (311032424107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155516212068 + 155516212069.

It is an arithmetic number, because the mean of its divisors is an integer number (155516212069).

Almost surely, 2311032424137 is an apocalyptic number.

It is an amenable number.

311032424137 is a deficient number, since it is larger than the sum of its proper divisors (1).

311032424137 is an equidigital number, since it uses as much as digits as its factorization.

311032424137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 311032424137 in words is "three hundred eleven billion, thirty-two million, four hundred twenty-four thousand, one hundred thirty-seven".