3110331131113 has 2 divisors, whose sum is σ = 3110331131114. Its totient is φ = 3110331131112.

The previous prime is 3110331131087. The next prime is 3110331131221. The reversal of 3110331131113 is 3111311330113.

3110331131113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2389754249689 + 720576881424 = 1545883^2 + 848868^2 .

It is a cyclic number.

It is not a de Polignac number, because 3110331131113 - 2⁵ = 3110331131081 is a prime.

It is not a weakly prime, because it can be changed into another prime (3110331138113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555165565556 + 1555165565557.

It is an arithmetic number, because the mean of its divisors is an integer number (1555165565557).

Almost surely, 2^{3110331131113} is an apocalyptic number.

It is an amenable number.

3110331131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110331131113 is an equidigital number, since it uses as much as digits as its factorization.

3110331131113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 3110331131113 its reverse (3111311330113), we get a palindrome (6221642461226).

The spelling of 3110331131113 in words is "three trillion, one hundred ten billion, three hundred thirty-one million, one hundred thirty-one thousand, one hundred thirteen".