Base | Representation |
---|---|
bin | 100011010111000111100001… |
… | …1010000001111110111100010 |
3 | 1111210022011221002212201020002 |
4 | 1012232033003100033313202 |
5 | 311232041432140103232 |
6 | 3021310012213420002 |
7 | 122341635566622062 |
oct | 10656170320176742 |
9 | 1453264832781202 |
10 | 311040512425442 |
11 | 9011a5a4500278 |
12 | 2aa7589a33a602 |
13 | 10472cc0ac4037 |
14 | 56b46266473a2 |
15 | 25e5d269beb62 |
hex | 11ae3c340fde2 |
311040512425442 has 4 divisors (see below), whose sum is σ = 466560768638166. Its totient is φ = 155520256212720.
The previous prime is 311040512425429. The next prime is 311040512425483. The reversal of 311040512425442 is 244524215040113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 178192089997321 + 132848422428121 = 13348861^2 + 11525989^2 .
It is a junction number, because it is equal to n+sod(n) for n = 311040512425396 and 311040512425405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77760128106359 + ... + 77760128106362.
Almost surely, 2311040512425442 is an apocalyptic number.
311040512425442 is a deficient number, since it is larger than the sum of its proper divisors (155520256212724).
311040512425442 is a wasteful number, since it uses less digits than its factorization.
311040512425442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155520256212723.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 311040512425442 its reverse (244524215040113), we get a palindrome (555564727465555).
The spelling of 311040512425442 in words is "three hundred eleven trillion, forty billion, five hundred twelve million, four hundred twenty-five thousand, four hundred forty-two".
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