3110442113 has 2 divisors, whose sum is σ = 3110442114. Its totient is φ = 3110442112.

The previous prime is 3110442089. The next prime is 3110442131. The reversal of 3110442113 is 3112440113.

Together with next prime (3110442131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1627961104 + 1482481009 = 40348^2 + 38503^2 .

It is an emirp because it is prime and its reverse (3112440113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3110442113 - 2¹⁴ = 3110425729 is a prime.

It is not a weakly prime, because it can be changed into another prime (3110442913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555221056 + 1555221057.

It is an arithmetic number, because the mean of its divisors is an integer number (1555221057).

Almost surely, 2^3110442113 is an apocalyptic number.

It is an amenable number.

3110442113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110442113 is an equidigital number, since it uses as much as digits as its factorization.

3110442113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 3110442113 is about 55771.3377372284. The cubic root of 3110442113 is about 1459.7350668650.

Adding to 3110442113 its reverse (3112440113), we get a palindrome (6222882226).

The spelling of 3110442113 in words is "three billion, one hundred ten million, four hundred forty-two thousand, one hundred thirteen".