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31110012021113 is a prime number
BaseRepresentation
bin1110001001011010111010…
…01101110010100101111001
311002011002101020010220012122
413010231131031302211321
513034201301034133423
6150055424153051025
76360424046033534
oct704553515624571
9132132336126178
1031110012021113
119a04755827763
1235a53b40b6a75
13144887a55346c
14797a38425a1b
1538e39970e8c8
hex1c4b5d372979

31110012021113 has 2 divisors, whose sum is σ = 31110012021114. Its totient is φ = 31110012021112.

The previous prime is 31110012021089. The next prime is 31110012021169. The reversal of 31110012021113 is 31112021001113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23225103093049 + 7884908928064 = 4819243^2 + 2808008^2 .

It is a cyclic number.

It is not a de Polignac number, because 31110012021113 - 210 = 31110012020089 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 31110012021091 and 31110012021100.

It is not a weakly prime, because it can be changed into another prime (31110012021313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555006010556 + 15555006010557.

It is an arithmetic number, because the mean of its divisors is an integer number (15555006010557).

Almost surely, 231110012021113 is an apocalyptic number.

It is an amenable number.

31110012021113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31110012021113 is an equidigital number, since it uses as much as digits as its factorization.

31110012021113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 31110012021113 its reverse (31112021001113), we get a palindrome (62222033022226).

The spelling of 31110012021113 in words is "thirty-one trillion, one hundred ten billion, twelve million, twenty-one thousand, one hundred thirteen".