Base | Representation |
---|---|
bin | 100011010111100101000110… |
… | …0110010011010011001001101 |
3 | 1111210112020212021111111111001 |
4 | 1012233022030302122121031 |
5 | 311234112014411102023 |
6 | 3021355114252500301 |
7 | 122346344466050641 |
oct | 10657121462323115 |
9 | 1453466767444431 |
10 | 311104023144013 |
11 | 90144525666140 |
12 | 2aa86063a7a691 |
13 | 10478ca29a1498 |
14 | 56b772d488c21 |
15 | 25e77e254a6ad |
hex | 11af28cc9a64d |
311104023144013 has 16 divisors (see below), whose sum is σ = 346609809997056. Its totient is φ = 276802261079040.
The previous prime is 311104023143987. The next prime is 311104023144053. The reversal of 311104023144013 is 310441320401113.
It is a cyclic number.
It is not a de Polignac number, because 311104023144013 - 213 = 311104023135821 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311104023144053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68309245 + ... + 72721117.
It is an arithmetic number, because the mean of its divisors is an integer number (21663113124816).
Almost surely, 2311104023144013 is an apocalyptic number.
It is an amenable number.
311104023144013 is a deficient number, since it is larger than the sum of its proper divisors (35505786853043).
311104023144013 is a wasteful number, since it uses less digits than its factorization.
311104023144013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4548324.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 311104023144013 its reverse (310441320401113), we get a palindrome (621545343545126).
The spelling of 311104023144013 in words is "three hundred eleven trillion, one hundred four billion, twenty-three million, one hundred forty-four thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •