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311104023144013 = 11471363934411873
BaseRepresentation
bin100011010111100101000110…
…0110010011010011001001101
31111210112020212021111111111001
41012233022030302122121031
5311234112014411102023
63021355114252500301
7122346344466050641
oct10657121462323115
91453466767444431
10311104023144013
1190144525666140
122aa86063a7a691
1310478ca29a1498
1456b772d488c21
1525e77e254a6ad
hex11af28cc9a64d

311104023144013 has 16 divisors (see below), whose sum is σ = 346609809997056. Its totient is φ = 276802261079040.

The previous prime is 311104023143987. The next prime is 311104023144053. The reversal of 311104023144013 is 310441320401113.

It is a cyclic number.

It is not a de Polignac number, because 311104023144013 - 213 = 311104023135821 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311104023144053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68309245 + ... + 72721117.

It is an arithmetic number, because the mean of its divisors is an integer number (21663113124816).

Almost surely, 2311104023144013 is an apocalyptic number.

It is an amenable number.

311104023144013 is a deficient number, since it is larger than the sum of its proper divisors (35505786853043).

311104023144013 is a wasteful number, since it uses less digits than its factorization.

311104023144013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4548324.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 311104023144013 its reverse (310441320401113), we get a palindrome (621545343545126).

The spelling of 311104023144013 in words is "three hundred eleven trillion, one hundred four billion, twenty-three million, one hundred forty-four thousand, thirteen".

Divisors: 1 11 47 517 136393 1500323 4411873 6410471 48530603 70515181 207358031 2280938341 601748594089 6619234534979 28282183922183 311104023144013