Base | Representation |
---|---|
bin | 1001000011011111011… |
… | …10011110100100000111 |
3 | 1002202000221022012102012 |
4 | 10201233232132210013 |
5 | 20044124144200403 |
6 | 354531204004435 |
7 | 31322435134550 |
oct | 4415756364407 |
9 | 1082027265365 |
10 | 311112100103 |
11 | 10aa3a740602 |
12 | 5036699071b |
13 | 2345104547c |
14 | 110b4c73327 |
15 | 815cee2ed8 |
hex | 486fb9e907 |
311112100103 has 4 divisors (see below), whose sum is σ = 355556685840. Its totient is φ = 266667514368.
The previous prime is 311112100087. The next prime is 311112100111. The reversal of 311112100103 is 301001211113.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311112100103 - 24 = 311112100087 is a prime.
It is a super-2 number, since 2×3111121001032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311112100153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22222292858 + ... + 22222292871.
It is an arithmetic number, because the mean of its divisors is an integer number (88889171460).
Almost surely, 2311112100103 is an apocalyptic number.
311112100103 is a deficient number, since it is larger than the sum of its proper divisors (44444585737).
311112100103 is an equidigital number, since it uses as much as digits as its factorization.
311112100103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44444585736.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 311112100103 its reverse (301001211113), we get a palindrome (612113311216).
The spelling of 311112100103 in words is "three hundred eleven billion, one hundred twelve million, one hundred thousand, one hundred three".
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