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31111313153 is a prime number
BaseRepresentation
bin11100111110011000…
…001111011100000001
32222022012102110102112
4130332120033130001
51002203444010103
622143051225105
72150652540614
oct347630173401
988265373375
1031111313153
1112215586058
126043148195
132c1a6a724b
141711c9017b
15c21496cd8
hex73e60f701

31111313153 has 2 divisors, whose sum is σ = 31111313154. Its totient is φ = 31111313152.

The previous prime is 31111313111. The next prime is 31111313159. The reversal of 31111313153 is 35131311113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31110962689 + 350464 = 176383^2 + 592^2 .

It is a cyclic number.

It is not a de Polignac number, because 31111313153 - 210 = 31111312129 is a prime.

It is a super-2 number, since 2×311113131532 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31111313159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555656576 + 15555656577.

It is an arithmetic number, because the mean of its divisors is an integer number (15555656577).

Almost surely, 231111313153 is an apocalyptic number.

It is an amenable number.

31111313153 is a deficient number, since it is larger than the sum of its proper divisors (1).

31111313153 is an equidigital number, since it uses as much as digits as its factorization.

31111313153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 405, while the sum is 23.

Adding to 31111313153 its reverse (35131311113), we get a palindrome (66242624266).

The spelling of 31111313153 in words is "thirty-one billion, one hundred eleven million, three hundred thirteen thousand, one hundred fifty-three".