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3111211213241 is a prime number
BaseRepresentation
bin101101010001100010101…
…000111010000110111001
3102000102120122210021000212
4231101202220322012321
5401433230032310431
610341134245440505
7440530466654345
oct55214250720671
912012518707025
103111211213241
11a9a50369126a
12422b82410135
13197502c49121
14aa824cc8625
1555de2d3e72b
hex2d462a3a1b9

3111211213241 has 2 divisors, whose sum is σ = 3111211213242. Its totient is φ = 3111211213240.

The previous prime is 3111211213211. The next prime is 3111211213249. The reversal of 3111211213241 is 1423121121113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2304412044841 + 806799168400 = 1518029^2 + 898220^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111211213241 - 26 = 3111211213177 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111211213249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555605606620 + 1555605606621.

It is an arithmetic number, because the mean of its divisors is an integer number (1555605606621).

Almost surely, 23111211213241 is an apocalyptic number.

It is an amenable number.

3111211213241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111211213241 is an equidigital number, since it uses as much as digits as its factorization.

3111211213241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 288, while the sum is 23.

Adding to 3111211213241 its reverse (1423121121113), we get a palindrome (4534332334354).

The spelling of 3111211213241 in words is "three trillion, one hundred eleven billion, two hundred eleven million, two hundred thirteen thousand, two hundred forty-one".