Base | Representation |
---|---|
bin | 101101010001100010101… |
… | …100011010011010110111 |
3 | 102000102120201111221100211 |
4 | 231101202230122122313 |
5 | 401433230301211043 |
6 | 10341134321250251 |
7 | 440530510532122 |
oct | 55214254323267 |
9 | 12012521457324 |
10 | 3111212132023 |
11 | a9a504159596 |
12 | 422b82793987 |
13 | 1975031ab398 |
14 | aa8250873b9 |
15 | 55de2e71a9d |
hex | 2d462b1a6b7 |
3111212132023 has 8 divisors (see below), whose sum is σ = 3263284032192. Its totient is φ = 2962718394336.
The previous prime is 3111212132011. The next prime is 3111212132051. The reversal of 3111212132023 is 3202312121113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3111212132023 - 241 = 912188876471 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3111212131985 and 3111212132003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111212132723) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 894538840 + ... + 894542317.
It is an arithmetic number, because the mean of its divisors is an integer number (407910504024).
Almost surely, 23111212132023 is an apocalyptic number.
3111212132023 is a deficient number, since it is larger than the sum of its proper divisors (152071900169).
3111212132023 is a wasteful number, since it uses less digits than its factorization.
3111212132023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1789081241.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3111212132023 its reverse (3202312121113), we get a palindrome (6313524253136).
The spelling of 3111212132023 in words is "three trillion, one hundred eleven billion, two hundred twelve million, one hundred thirty-two thousand, twenty-three".
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