Base | Representation |
---|---|
bin | 1110001001011110111010… |
… | …10111101111001011101001 |
3 | 11002011021221001220211202002 |
4 | 13010233131113233023221 |
5 | 13034220202000042413 |
6 | 150100421401020345 |
7 | 6360531244355006 |
oct | 704573527571351 |
9 | 132137831824662 |
10 | 31112162112233 |
11 | 9a05659468a74 |
12 | 35a58b41846b5 |
13 | 1448b30b2c027 |
14 | 797b9dbd08ad |
15 | 38e47336d958 |
hex | 1c4bdd5ef2e9 |
31112162112233 has 2 divisors, whose sum is σ = 31112162112234. Its totient is φ = 31112162112232.
The previous prime is 31112162112211. The next prime is 31112162112253. The reversal of 31112162112233 is 33221126121113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30703600812889 + 408561299344 = 5541083^2 + 639188^2 .
It is a cyclic number.
It is not a de Polignac number, because 31112162112233 - 26 = 31112162112169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31112162112196 and 31112162112205.
It is not a weakly prime, because it can be changed into another prime (31112162112203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556081056116 + 15556081056117.
It is an arithmetic number, because the mean of its divisors is an integer number (15556081056117).
Almost surely, 231112162112233 is an apocalyptic number.
It is an amenable number.
31112162112233 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112162112233 is an equidigital number, since it uses as much as digits as its factorization.
31112162112233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 29.
Adding to 31112162112233 its reverse (33221126121113), we get a palindrome (64333288233346).
The spelling of 31112162112233 in words is "thirty-one trillion, one hundred twelve billion, one hundred sixty-two million, one hundred twelve thousand, two hundred thirty-three".
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