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3111221131313 is a prime number
BaseRepresentation
bin101101010001100011001…
…110101111100000110001
3102000102121100110011001212
4231101203032233200301
5401433240102200223
610341135242205505
7440530650163121
oct55214316574061
912012540404055
103111221131313
11a9a509245919
12422b857b3895
1319750500c5c9
14aa82634ac81
1555de3b4d278
hex2d4633af831

3111221131313 has 2 divisors, whose sum is σ = 3111221131314. Its totient is φ = 3111221131312.

The previous prime is 3111221131297. The next prime is 3111221131327. The reversal of 3111221131313 is 3131311221113.

3111221131313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2891741062144 + 219480069169 = 1700512^2 + 468487^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111221131313 - 24 = 3111221131297 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111221136313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555610565656 + 1555610565657.

It is an arithmetic number, because the mean of its divisors is an integer number (1555610565657).

Almost surely, 23111221131313 is an apocalyptic number.

It is an amenable number.

3111221131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111221131313 is an equidigital number, since it uses as much as digits as its factorization.

3111221131313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324, while the sum is 23.

Adding to 3111221131313 its reverse (3131311221113), we get a palindrome (6242532352426).

The spelling of 3111221131313 in words is "three trillion, one hundred eleven billion, two hundred twenty-one million, one hundred thirty-one thousand, three hundred thirteen".