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3111243828233 is a prime number
BaseRepresentation
bin101101010001100100100…
…101010100110000001001
3102000102122221011021101112
4231101210211110300021
5401433311410000413
610341141412500105
7440531344123652
oct55214445246011
912012587137345
103111243828233
11a9a520038402
12422b9131a635
13197509928438
14aa829378529
1555de5b332a8
hex2d464954c09

3111243828233 has 2 divisors, whose sum is σ = 3111243828234. Its totient is φ = 3111243828232.

The previous prime is 3111243828179. The next prime is 3111243828241. The reversal of 3111243828233 is 3328283421113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1636639193344 + 1474604634889 = 1279312^2 + 1214333^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3111243828233 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111243828293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555621914116 + 1555621914117.

It is an arithmetic number, because the mean of its divisors is an integer number (1555621914117).

Almost surely, 23111243828233 is an apocalyptic number.

It is an amenable number.

3111243828233 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111243828233 is an equidigital number, since it uses as much as digits as its factorization.

3111243828233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 165888, while the sum is 41.

The spelling of 3111243828233 in words is "three trillion, one hundred eleven billion, two hundred forty-three million, eight hundred twenty-eight thousand, two hundred thirty-three".