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311125553513 is a prime number
BaseRepresentation
bin1001000011100001000…
…01110011000101101001
31002202001212121201000122
410201300201303011221
520044141120203023
6354532404213025
731322660366405
oct4416041630551
91082055551018
10311125553513
1110aa4729a325
125036b39a175
1323453a75b78
14110b6976105
15815e29e2c8
hex4870873169

311125553513 has 2 divisors, whose sum is σ = 311125553514. Its totient is φ = 311125553512.

The previous prime is 311125553461. The next prime is 311125553521. The reversal of 311125553513 is 315355521113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 310837470784 + 288082729 = 557528^2 + 16973^2 .

It is an emirp because it is prime and its reverse (315355521113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311125553513 - 220 = 311124504937 is a prime.

It is a super-2 number, since 2×3111255535132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311125553573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155562776756 + 155562776757.

It is an arithmetic number, because the mean of its divisors is an integer number (155562776757).

Almost surely, 2311125553513 is an apocalyptic number.

It is an amenable number.

311125553513 is a deficient number, since it is larger than the sum of its proper divisors (1).

311125553513 is an equidigital number, since it uses as much as digits as its factorization.

311125553513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 33750, while the sum is 35.

The spelling of 311125553513 in words is "three hundred eleven billion, one hundred twenty-five million, five hundred fifty-three thousand, five hundred thirteen".