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311130030121102 = 2155565015060551
BaseRepresentation
bin100011010111110001001101…
…0111011001010000010001110
31111210121201222202012211011201
41012233202122323022002032
5311240023300202333402
63021415055044340114
7122351255121522403
oct10657423273120216
91453551882184151
10311130030121102
1190154560950a35
122aa8b1016a463a
131047b588a1881a
1456b8ab94782aa
1525e831582b687
hex11af89aeca08e

311130030121102 has 4 divisors (see below), whose sum is σ = 466695045181656. Its totient is φ = 155565015060550.

The previous prime is 311130030121091. The next prime is 311130030121117. The reversal of 311130030121102 is 201121030031113.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 311130030121102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77782507530274 + ... + 77782507530277.

It is an arithmetic number, because the mean of its divisors is an integer number (116673761295414).

Almost surely, 2311130030121102 is an apocalyptic number.

311130030121102 is a deficient number, since it is larger than the sum of its proper divisors (155565015060554).

311130030121102 is a wasteful number, since it uses less digits than its factorization.

311130030121102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155565015060553.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 311130030121102 its reverse (201121030031113), we get a palindrome (512251060152215).

The spelling of 311130030121102 in words is "three hundred eleven trillion, one hundred thirty billion, thirty million, one hundred twenty-one thousand, one hundred two".

Divisors: 1 2 155565015060551 311130030121102