Base | Representation |
---|---|
bin | 101101010001101000000… |
… | …011101110111000010111 |
3 | 102000102210222212101001112 |
4 | 231101220003232320113 |
5 | 401433421321144343 |
6 | 10341151254245235 |
7 | 440532652522346 |
oct | 55215003567027 |
9 | 12012728771045 |
10 | 3111302131223 |
11 | a9a54aa3a2a0 |
12 | 422ba895681b |
13 | 197518a2cb50 |
14 | aa832dd3b5d |
15 | 55deaced218 |
hex | 2d4680eee17 |
3111302131223 has 32 divisors (see below), whose sum is σ = 3797508536640. Its totient is φ = 2510032573440.
The previous prime is 3111302131219. The next prime is 3111302131247. The reversal of 3111302131223 is 3221312031113.
3111302131223 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3111302131223 - 22 = 3111302131219 is a prime.
It is a super-2 number, since 2×31113021312232 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111302131213) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 643736 + ... + 2576237.
It is an arithmetic number, because the mean of its divisors is an integer number (118672141770).
Almost surely, 23111302131223 is an apocalyptic number.
3111302131223 is a deficient number, since it is larger than the sum of its proper divisors (686206405417).
3111302131223 is a wasteful number, since it uses less digits than its factorization.
3111302131223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3220259.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3111302131223 its reverse (3221312031113), we get a palindrome (6332614162336).
The spelling of 3111302131223 in words is "three trillion, one hundred eleven billion, three hundred two million, one hundred thirty-one thousand, two hundred twenty-three".
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